x^2+4x+3x+12=x^2+2x+x+2

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Solution for x^2+4x+3x+12=x^2+2x+x+2 equation: 



x^2+4x+3x+12=x^2+2x+x+2

We move all terms to the left:

x^2+4x+3x+12-(x^2+2x+x+2)=0

We add all the numbers together, and all the variables

x^2+7x-(x^2+2x+x+2)+12=0

We get rid of parentheses

x^2-x^2+7x-2x-x-2+12=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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